问题
填空题
数列1,
|
答案
∵an=
=1 1+2+3++n
=2(2 n(n+1)
-1 n
),1 n+1
∴Sn=2(1-
+1 2
-1 2
+1 3
-1 3
++1 4
-1 n
),1 n+1
=2(1-
)=1 n+1
.2n n+1
故答案为:2n n+1
数列1,
|
∵an=
=1 1+2+3++n
=2(2 n(n+1)
-1 n
),1 n+1
∴Sn=2(1-
+1 2
-1 2
+1 3
-1 3
++1 4
-1 n
),1 n+1
=2(1-
)=1 n+1
.2n n+1
故答案为:2n n+1