问题
解答题
Sn=
|
答案
因为an=
=1 n(n+1)(n+2)
[1 2
-1 n(n+1)
]1 (n+1)(n+2)
所以Sn=
[1 2
-1 1×2
+1 2×3
-1 2×3
+…+1 3×4
-1 n(n+1)
]1 (n+1)(n+2)
=
[1 2
-1 2
]1 (n+1)(n+2)
=n(n+3) 4(n+1)(n+2)
Sn=
|
因为an=
=1 n(n+1)(n+2)
[1 2
-1 n(n+1)
]1 (n+1)(n+2)
所以Sn=
[1 2
-1 1×2
+1 2×3
-1 2×3
+…+1 3×4
-1 n(n+1)
]1 (n+1)(n+2)
=
[1 2
-1 2
]1 (n+1)(n+2)
=n(n+3) 4(n+1)(n+2)