问题
解答题
已知数列an=
|
答案
令bn=
=n (n+1) !
-1 n !
则1 (n+1) !
an=b1+b2+…+bn=(
-1 1 !
)+(1 2 !
-1 2 !
)+…+[(1 3 !
-1 n !
)]1 (n+1) ! =1- 1 (n+1) !
故有 a2008=1-
.1 2009 !
已知数列an=
|
令bn=
=n (n+1) !
-1 n !
则1 (n+1) !
an=b1+b2+…+bn=(
-1 1 !
)+(1 2 !
-1 2 !
)+…+[(1 3 !
-1 n !
)]1 (n+1) ! =1- 1 (n+1) !
故有 a2008=1-
.1 2009 !