问题
选择题
若(1+x)n+1的展开式中含xn-1的系数为an,则
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答案
由题意可得
an=Cn+1n-112=Cn+12=
,∴(n+1)•n 2
=1 an
=2•(2 n(n+1)
-1 n
),1 n+1
∴
+1 a1
+…+1 a2 1 an
=2(
-1 1
+1 2
-1 2
++1 3
-1 n
)1 n+1
=2(
-1 n
)=1 n+1
.2n n+1
故选项为B