问题
填空题
若数列{an}的通项an=
|
答案
∵an=
(-C n6
)n,1 2
∴S6=
(-C 16
)1+1 2
(-C 26
)2+1 2
(-C 36
)3+1 2
(-C 46
)4+1 2
(-C 56
)5+1 2
(-C 66
)61 2
=(1-
)6-11 2
=-63 64
故答案为:-63 64
若数列{an}的通项an=
|
∵an=
(-C n6
)n,1 2
∴S6=
(-C 16
)1+1 2
(-C 26
)2+1 2
(-C 36
)3+1 2
(-C 46
)4+1 2
(-C 56
)5+1 2
(-C 66
)61 2
=(1-
)6-11 2
=-63 64
故答案为:-63 64