问题
解答题
(1)-
(2)先简化,再求值:5xy2-2x2y+[3xy2-(4xy2-2x2y)],其中x=-2,y=-1. |
答案
(1)原式=-
×(-9×3 2
-8)-1=-4 9
×(-12)-1=18-1=17;3 2
(2)原式=5xy2-2x2y+3xy2-4xy2+2x2y=4xy2,
当x=-2,y=-1时,原式=4×(-2)×1=-8.
(1)-
(2)先简化,再求值:5xy2-2x2y+[3xy2-(4xy2-2x2y)],其中x=-2,y=-1. |
(1)原式=-
×(-9×3 2
-8)-1=-4 9
×(-12)-1=18-1=17;3 2
(2)原式=5xy2-2x2y+3xy2-4xy2+2x2y=4xy2,
当x=-2,y=-1时,原式=4×(-2)×1=-8.