问题 解答题
(1)
108
+
45
+
1
1
3
-
125
        
(2)8x3+125=0
(3)(3
2
+
48
)(
18
-4
3
)
   
(4)(3+
10
)2006(3-
10
)2005

(5)
4
-(
1
5+2
)0+(-2)3÷3-1
   
(6)
(1-
2
)2
+
3(2-
2
)3
+|π-4|+
(π-3.14)2
答案

(1)原式=6

3
+3
5
+
2
3
3
-5
5

=

20
3
-2
5

(2)方程变形得:x3=-

125
8

解得:x=-

5
2

(3)原式=(3

2
-4
3
)(3
2
+4
3

=(3

2
2-(4
3
2

=-30;

(4)原式=(3+

10
)[(3+
10
)(3-
10
)]2005

=-3-

10

(5)原式=2-1-8×3

=-23;

(6)原式=

2
-1+2-
2
+4-π+π-3.14

=1.86.

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