问题 解答题
计算:
(1)(2m2n-32•(-mn-2-2
(2)4x2y-3z÷(-2x-1yz-22
(3)(
1
2
)-3-23×0.125+20060+|-1|

(4)2×(π-3.14)0+8×(3×2)-1+(-
1
2
)-4
答案

(1)原式=4m4n-6•m-2n4

=4m2n-2

(2)原式=4x2y-3z÷(4x-2y2z-4

=x4y-5z5

(3)原式=8-8×0.125+1+1

=-8-1+1+1

=-7;

(4)原式=2×1+8×

1
6
+16

=2+

4
3
+16

=19

1
3

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