问题
解答题
计算: (1)(2m2n-3)2•(-mn-2)-2; (2)4x2y-3z÷(-2x-1yz-2)2; (3)(
(4)2×(π-3.14)0+8×(3×2)-1+(-
|
答案
(1)原式=4m4n-6•m-2n4
=4m2n-2;
(2)原式=4x2y-3z÷(4x-2y2z-4)
=x4y-5z5;
(3)原式=8-8×0.125+1+1
=-8-1+1+1
=-7;
(4)原式=2×1+8×
+161 6
=2+
+164 3
=19
.1 3