问题
解答题
计算: (1)
(2)3
(3)(π+1)0-
|
答案
(1)原式=
÷32
-2
÷8 2
=4-2
=2;
(2)原式=3×3
-2
×41 2
+7×2 2 4
=9
-22
+2 7 2 4
=
;35 2 4
(3)原式=1-2
+3
-(3-2)3
=-
.3
计算: (1)
(2)3
(3)(π+1)0-
|
(1)原式=
÷32
-2
÷8 2
=4-2
=2;
(2)原式=3×3
-2
×41 2
+7×2 2 4
=9
-22
+2 7 2 4
=
;35 2 4
(3)原式=1-2
+3
-(3-2)3
=-
.3