问题
问答题 简答题
计算题：一台阳离子交换器直径D＝3.0m，树脂层高H＝1.6m，树脂的工作交换容量E＝800mol／m3，问再生时需用浓度为31%的工业盐酸多少升？
答案
参考答案：
V＝（D／2）2πhEM／（1000×31%）＝（3.0／2）2×3.14×1.6×800×36.5／310＝1065（L）
再生时需用浓度为31%的工业盐酸1065L。
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计算题：一台阳离子交换器直径D＝3.0m，树脂层高H＝1.6m，树脂的工作交换容量E＝800mol／m3，问再生时需用浓度为31%的工业盐酸多少升？
参考答案：
V＝（D／2）2πhEM／（1000×31%）＝（3.0／2）2×3.14×1.6×800×36.5／310＝1065（L）
再生时需用浓度为31%的工业盐酸1065L。
| 阅读理解。 | |
for one to cross at a time. Meeting at the middle of the bridge, neither would give the way to the other. They locked horns, and fought for the right of way, until both fell into the torrent below and were drowned. | |
| 1. The goats _____________ the bridge. | |
| A. was crossing B. have crossed C. were crossing | |
| 2. The bridge was _____________. | |
| A. wide B. rude C. smooth | |
| 3. They fought _____________ their horns. | |
| A. in B. with C. use | |
| 4. The goats were fighting at the _____________ of the bridge. | |
| A. middle B. front C. back |