问题
解答题
计算题 (1)-21-12+33+12-67 (2)(
(3)48÷[(-2)3-(-4)] (4)(-1)3×(-5)÷[(-3)2+2×(-5)]. |
答案
(1)原式=(-21-12-67)+(33+12)
=-110+45
=-55;
(2)原式=(
-1 2
+3 4
-5 6
)×(-36)7 12
=-18+27-30+21
=0;
(3)原式=48÷(-8+4)
=48÷(-4)
=-12;
(4)原式=-1×(-5)÷(9-10)
=-1×(-5)÷(-1)
=-5.