问题
解答题
(1)-22+(-2)4×(
(2)3(x2-2xy)-[3x2-2y+2(xy+y)]. |
答案
(1)原式=-4+16×
1 |
8 |
1 |
100 |
=-4+2-0.28×100
=-4+2-28
=-30;
(2)原式=3x2-6xy-【3x2-2y+2xy+2y】
=3x2-6xy-3x2+2y-2xy-2y
=-8xy.
(1)-22+(-2)4×(
(2)3(x2-2xy)-[3x2-2y+2(xy+y)]. |
(1)原式=-4+16×
1 |
8 |
1 |
100 |
=-4+2-0.28×100
=-4+2-28
=-30;
(2)原式=3x2-6xy-【3x2-2y+2xy+2y】
=3x2-6xy-3x2+2y-2xy-2y
=-8xy.