问题
解答题
(1)计算:(2010-π)0-(
(2)先化简,再求值:
|
答案
(1)原式=1-2+1-(
-2)5
=-
+25
=2-
.5
(2)原式=
-(a+1)2 (a+1)(a-1) a a-1
=
-a+1 a-1 a a-1
=
.1 a-1
当a=
+1时,3
原式=
=1 3
.3 3
(1)计算:(2010-π)0-(
(2)先化简,再求值:
|
(1)原式=1-2+1-(
-2)5
=-
+25
=2-
.5
(2)原式=
-(a+1)2 (a+1)(a-1) a a-1
=
-a+1 a-1 a a-1
=
.1 a-1
当a=
+1时,3
原式=
=1 3
.3 3