问题 填空题
设数列{an},{bn}都是正项等比数列,Sn,Tn分别为数列{lgan}与{lgbn}的前n项和,且
Sn
Tn
=
n
2n+1
,则logb5a5=______.
答案

设正项等比数列{an}的公比为q,设正项等比数列{bn}的公比为p,则数列{lgan}是等差数列,公差为lgq,{lgbn}是等差数列,公差为lgp.

故Sn =n•lga1+

n(n-1)
2
•lgq,同理可得 Tn =n•lgb1+
n(n-1)
2
•lgp

Sn
Tn
=
n
2n+1
=
lga1+
n-1
2
lgq
lgb1+
n-1
2
lgp

logb5a5=

lga5
lgb5
=
lga1+4lgq
lgb1+4lgp
=
S9
T9
=
9
19

故答案为

9
19

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