问题
解答题
计算:
|
答案
∵
=1 n(n+2)
(1 2
-1 n
),1 n+2
∴原式=
(1 2
-1 1
)+1 3
(1 2
-1 3
)+1 5
(1 2
-1 5
)+…+1 7
(1 2
-1 99
)1 101
=
(1-1 2
+1 3
-1 3
+1 5
-1 5
+…+1 7
-1 99
)1 101
=
(1-1 2
)1 101
=
.50 101