问题
选择题
|
答案
∵
=1 n(n+2)
(1 2
-1 n
),1 n+2
∴
+1 1×3
+1 2×4
+1 3×5
+…+1 4×6 1 n(n+2)
=
[(1-1 2
)+(1 3
-1 2
)+(1 4
-1 3
)+(1 5
-1 4
)+…+(1 6
-1 n-2
)+(1 n
-1 n-1
)+(1 n+1
-1 n
)]1 n+2
=
(1+1 2
-1 2
-1 n+1
)1 n+2
=
(1 2
-3 2
-1 n+1
),1 n+2
故答案选C.