问题
解答题
计算下列各题 (1)-23÷(-
(2)199
(3)[3
(4)-0.52+(-
|
答案
(1)-23÷(-
)2+9×(-1 2
)3-(-1)1001 3
=-8÷
+9×(-1 4
)-11 27
=-8×4+(-
)-11 3
=(-32)+(-1)+(-
)1 3
=-33
;1 3
(2)199
×(-5)198 199
=(200-
)×(-5)1 199
=200×(-5)+(-
)×(-5)1 199
=-1000+5 199
=-(1000-
)5 199
=-999
;194 199
(3)[3
÷(-1 3
)×2 3
]4-2×(-3)3-(-5)21 5
=[
×(-10 3
)×3 2
]4-2×(-27)-251 5
=(-1)4+54-25
=1+54-25
=55-25
=30;
(4)-0.52+(-
)2-|-22-4|-(-11 2
)3×(1 2
)3÷(-1 3
)41 2
=-0.25+
-|-4-4|-1 4
×27 8
÷1 27
,1 16
=-0.25+0.25-8-
×16,1 8
=-8-2
=(-8)+(-2)
=-10.