问题
解答题
计算 (1)
(2)(
(3)(-
|
答案
(1)原式=
=(x+y)2 (x+y)(x-y)
;x+y x-y
(2)原式=
×(x-2)=4+x-2 (x+2)(x-2)
×(x-2)=1;1 x-2
(3)原式=4+1-5=0.
计算 (1)
(2)(
(3)(-
|
(1)原式=
=(x+y)2 (x+y)(x-y)
;x+y x-y
(2)原式=
×(x-2)=4+x-2 (x+2)(x-2)
×(x-2)=1;1 x-2
(3)原式=4+1-5=0.