问题
解答题
(1)计算:(-1)2011-(
(2)计算:(
(3)计算:
|
答案
(1)原式=-1-1+2=0;
(2)原式=(x-4)
=x;x x-4
(3)原式=
-2m (m+3)(m-3)
=m-3 (m+3)(m-3)
=2m-(m-3) (m+3)(m-3)
.1 m-3
(1)计算:(-1)2011-(
(2)计算:(
(3)计算:
|
(1)原式=-1-1+2=0;
(2)原式=(x-4)
=x;x x-4
(3)原式=
-2m (m+3)(m-3)
=m-3 (m+3)(m-3)
=2m-(m-3) (m+3)(m-3)
.1 m-3