问题 解答题
计算
(1)(-
1
2
)-1-23×0.125+(
3-27
-2012)0

(2)(
-a
b
)2÷(
2a2
5b
)2
a
5b

(3)
m+2n
n-m
+
n
m-n
-
2n
n-m

(4)(
x
x-y
-
2y
x-y
)•
xy
x-2y
÷(
1
x
+
1
y
)
答案

(1)原式=-2+8×0.125+1

=-2+1+1

=0;

(2)原式=

a2
b2
÷
4a4
25b2
a
5b

=

a2
b2
25b2
4a2
a
5b

=

5a
4b

(3)原式=

m+2n
n-m
-
n
n-m
-
2n
n-m

=

m+2n-n-2n
n-m

=

m-n
n-m

=-1;

(4)原式=

x-2y
x-y
xy
x-2y
÷
x+y
xy

=

x-2y
x-y
xy
x-2y
xy
x+y

=

x2y2
x2-y2

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