问题
解答题
计算 (1)
(2)
(3)
(4)(-3ab-1)3. |
答案
(1)原式=2+1-3+2
=2;
(2)原式=x+1-1 x
=x x
=1;
(3)原式=
-a a2-b2 a-b a2-b2
=
;b a2-b2
(4)原式=(-3)3a3b-3
=-27a3 b3
计算 (1)
(2)
(3)
(4)(-3ab-1)3. |
(1)原式=2+1-3+2
=2;
(2)原式=x+1-1 x
=x x
=1;
(3)原式=
-a a2-b2 a-b a2-b2
=
;b a2-b2
(4)原式=(-3)3a3b-3
=-27a3 b3