问题 解答题
计算
(1)
4
+(-2013)0-(
1
3
)-1+
|-2|
(2)
x+1
x
-
1
x

(3)
a
a2-b2
-
1
a+b

(4)(-3ab-13
答案

(1)原式=2+1-3+2

=2;

(2)原式=

x+1-1
x

=

x
x

=1;

(3)原式=

a
a2-b2
-
a-b
a2-b2

=

b
a2-b2

(4)原式=(-3)3a3b-3

=-

27a3
b3

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