问题 解答题 (1)计算:(3.14-π)0-22×34+(-12)-3+|-3|(2)先化简:(x2-2xyy+y)÷x2-y2xy+y2,当x=2时,再从-1<y<2的范围内选取一个合适的整数y代入求值. 答案 (1)原式=1-4×34-8+3=-7;(2)原式=x2-2xy+y2y•y(x+y)(x+y)(x-y)=x-y,当x=2时,取y=1,原式=2-1=1.