问题
解答题
计算 (1)
(2)0.25×(-2)-2÷(16)-1-(π-3)0 (3)
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答案
(1)
-2 x+1
=1 x-1
-2(x-1) (x+1)(x-1)
=x+1 (x+1)(x-1)
;x-3 (x+1)(x-1)
(2)0.25×(-2)-2÷(16)-1-(π-3)0=
×1 4
÷1 4
-1=1 16
×16-1=0;1 16
(3)
•a-1 a+2
÷a2-4 a2-2a+1
=1 a2-1
•a-1 a+2
×(a+1)(a-1)=(a-2)(a+1)=a2-a-2.(a+2)(a-2) (a-1)2