问题
解答题
计算: (1)
(2)(-3)0-
|
答案
(1)原式=2
×(2
-2
)2 2
=2
×2
-22
×2 2 2
=4-2
=2;
(2)原式=1-3
+3
-1+2
-3 2 (
+3
)(2
-3
)2
=1-3
+3
-1+2
-3 2
=-2
.3
计算: (1)
(2)(-3)0-
|
(1)原式=2
×(2
-2
)2 2
=2
×2
-22
×2 2 2
=4-2
=2;
(2)原式=1-3
+3
-1+2
-3 2 (
+3
)(2
-3
)2
=1-3
+3
-1+2
-3 2
=-2
.3