问题
解答题
(1)解方程:x2-2x-1=0. (2)计算:(
(3)计算:-42+|
|
答案
(1)x2-2x-1=(x-1)2-2=0,
∴x-1=±
,2
∴x1=1+
;x2=1-2
;2
(2)(
-448
)-(31 8
-21 3
)0.5
=4
-3
-2
+3 2
=3
;3
(3)-42+|
-2|-(2002-2
)0+3 1 1+ 2
=-16+(2-
)-1+2 1- 2 (1+
)(1-2
)2
=-16+2-
-1-(1-2
)2
=-16