问题
选择题
如果△ABC∽△A′B′C′,且相似比是k1,△A′B′C′∽△ABC,且相似比是k2则( )
A.k1=k2
B.k1+A′B′=0
C.k1•k2=-1
D.k1•k2=1
答案
∵△ABC∽△A′B′C′
∴AB:A′B′=k1
而△A′B′C′∽△ABC
所以也能得到,A′B′:AB=k2
那么k1•k2=
×AB A′B′
=1.故选D.A′B′ AB
如果△ABC∽△A′B′C′,且相似比是k1,△A′B′C′∽△ABC,且相似比是k2则( )
A.k1=k2
B.k1+A′B′=0
C.k1•k2=-1
D.k1•k2=1
∵△ABC∽△A′B′C′
∴AB:A′B′=k1
而△A′B′C′∽△ABC
所以也能得到,A′B′:AB=k2
那么k1•k2=
×AB A′B′
=1.故选D.A′B′ AB