问题
填空题
如果
|
答案
+1 2
+1 6
+…1 12
=1 n(n+1)
,2003 2004
1-
+1 2
-1 2
+1 3
-1 3
+…+1 4
-1 n
=1 n+1
,2003 2004
1-
=1 n+1
,2003 2004
=n n+1
,2003 2004
∴n=2003.
故答案为:2003.
如果
|
+1 2
+1 6
+…1 12
=1 n(n+1)
,2003 2004
1-
+1 2
-1 2
+1 3
-1 3
+…+1 4
-1 n
=1 n+1
,2003 2004
1-
=1 n+1
,2003 2004
=n n+1
,2003 2004
∴n=2003.
故答案为:2003.