问题 解答题

计算:

(1)-32×0÷3-2+|-27|

(2)(2x2y)3-(-7xy2)÷(14x4y3

(3)(x-5)2-(x-2)(x-3)

(4)[(a+b)(a-b)+(a+b)2-2a2]÷(-2a)

答案

(1)原式=-9×1÷

1
9
+27

=-81+27

=-54;

(2)原式=(8x6y3)•(-7xy2)÷(14x4y3

=-4x3y2

(3)原式=x2-10x+25-(x2-3x-2x+6)

=x2-10x+25-x2+3x+2x-6

=-5x+19;

(4)原式=(a2-b2+a2+2ab+b2-2a2)÷(-2a)

=2ab÷(-2a)

=-b.

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