问题
解答题
计算: (1)|-5|-(π-3)0+(-
(2)(-3m+2n)+
(3)2a(a-1)-(a+1)(a-5) (4)(-
|
答案
(1)原式=5-1+
÷1 4 1 2
=5-1+1 2
=4
;1 2
(2)原式=-3m+2n+2m-n-1 3
=-m+n-
;1 3
(3)原式=2a2-2a-a2+5a-a+5
=a2+2a+5;
(4)原式=-
x6y3-1 8
x6y31 4
=-
x6y3.3 8