问题
解答题
计算: (1)|-2|-(1+
(2)
(3)2tan45°sin45°-4sin30°cos45°+
|
答案
(1)原式=2-1+2
=3;
(2)原式=2x
+3xx
-5xx x
=0;
(3)原式=2×1×
-4×2 2
×1 2
+2 2
×6 3 3
=
-2
+2 2
=
.2
计算: (1)|-2|-(1+
(2)
(3)2tan45°sin45°-4sin30°cos45°+
|
(1)原式=2-1+2
=3;
(2)原式=2x
+3xx
-5xx x
=0;
(3)原式=2×1×
-4×2 2
×1 2
+2 2
×6 3 3
=
-2
+2 2
=
.2