问题
解答题
计算:(1)(
(2)(x+y)0+2-2+(-
(3)(π-3.14)0+
(4)
(5)(-
(6)(2011-π)0-(-
|
答案
(1)(
-1)0+22+(-3
)-11 2
=1+4-2
=3;
(2)(x+y)0+2-2+(-
)-11 2
=1+
-21 4
=-
;3 4
(3)(π-3.14)0+
+(-18
)-1-|1-1 2
|2
=1+3
-2+1-2 2
=2
;2
(4)
+(4
)-1+(2-π)01 2
=2+2+1
=5;
(5)(-
)0+(-2)3+(1 2
)-1+|-2|1 3
=1-8+3+2
=-2;
(6)(2011-π)0-(-
)-2+|-4|1 2
=1-4+4
=1.