问题
填空题
已知正项等比数列{an}中,前n项和为Sn,若S8=17S4,则S5:S3=______.
答案
∵
=17,(q≠1),若q=1可得S8 S4
=2≠17,故q≠1,S8 S4
∴
=a1(1-q,8) 1-q a(1-q4) 1-q
=17,化简得1-q8=17(1-q4),可得q8-17q4+16=0,解得q4=1或16,q≠1,解得q=2,1-q8 1-q4
S5:S3=
=1-q5 1-q3
=q5-1 q3-1
=q2+q5-q2+q2-1 q3-1
=4+q+1 q2+q+1
=2+1 4+2+1
;31 7
故答案为:
;31 7