问题 解答题
计算:(1)(-1)2+(
1
2
-1-5
1
2
÷0(2)
3
x+2
-
1
x-2
+
2x
x2-4

(3)先化简,再求值:
2x+6
x2-4x+4
÷
x2+3x
x-2
-
1
x-2
,其中x=-1.
答案

(1)(-1)2+(

1
2
-1-5
1
2
÷0

=1+2-5

1
2
÷1

=3-5

1
2

=-2

1
2

(2)

3
x+2
-
1
x-2
+
2x
x2-4

=

3(x-2)
(x+2)(x-2)
-
x+2
(x+2)(x-2)
+
2x
(x+2)(x-2)

=

3x-6-x-2+2x
(x+2)(x-2)

=

4(x-2)
(x+2)(x-2)

=

4
x+2

(3)

2x+6
x2-4x+4
÷
x2+3x
x-2
-
1
x-2

=

2(x+3)
(x-2)2
x-2
x(x+3)
-
1
x-2

=

2
x(x-2)
-
x
x(x-2)

=

-(x-2)
x(x-2)

=-

1
x

当x=-1时,原式=-

1
-1
=1.

单项选择题
单项选择题