问题
解答题
计算下列各题: (1)-1-3-8-1×(-
(2)[(2x+1)(4x+2)-2]÷(-8x); (3)(3x+1)2-(3x-1)(3x+1) (4)( a-b-c )2 (5)已知:x+y=-1,xy=-6,求:x2+y2及x-y的值. |
答案
(1)原式=-1-
×4×01 8
=-1.5;
(2)原式=(8x2-8x+2-2)÷(-8x)
=-x-1;
(3)原式=[(x+2y)(x-2y)]2-(x-2y)(x+2y)(x2+4y2)
=(x2-4y2)2-(x2-4y2)(x2+4y2)
=x4-8x2y2+16y4-x4+16y4=32y4-8x2y2
(4)原式=(a-b)2-2ac+4bc+c2
=a2-4ab+4b2-2ac+4bc+c2
(5)原式=(x+y)2-2xy=13;
原式=±
=±5.(x+y)2-4xy