问题
解答题
计算 (1)2a2-a8÷a6 (2)2-2-(
(3)(
(4)3a3b2÷a2+b-(a2b-3ab-5a2b) |
答案
(1)原式=2a2-a2=a2;
(2)原式=
-1+1=1 4
;1 4
(3)原式=2-1+(0.25×4)4=2-1+1=2;
(4)原式=3ab2+a2b2-3ab2-5a2b2=-4a2b2.
计算 (1)2a2-a8÷a6 (2)2-2-(
(3)(
(4)3a3b2÷a2+b-(a2b-3ab-5a2b) |
(1)原式=2a2-a2=a2;
(2)原式=
-1+1=1 4
;1 4
(3)原式=2-1+(0.25×4)4=2-1+1=2;
(4)原式=3ab2+a2b2-3ab2-5a2b2=-4a2b2.