问题
解答题
计算: (1)(2-π)0-(
(2)(x+1)(x-1)-(x+2)2. |
答案
(1)原式=1-4+(-
×4)2011×(-4)=1-4+4=1;1 4
(2)原式=x2-1-(x2+4x+4)=x2-1-x2-4x-4=-4x-5.
计算: (1)(2-π)0-(
(2)(x+1)(x-1)-(x+2)2. |
(1)原式=1-4+(-
×4)2011×(-4)=1-4+4=1;1 4
(2)原式=x2-1-(x2+4x+4)=x2-1-x2-4x-4=-4x-5.