问题
解答题
计算: (1)|2
(2)
|
答案
(1)|2
-3|-(-2
)-2+1 2
,18
=3-2
-4+32
,2
=
-1;2
(2)
+sin45°cos45°,cos60° 3sin30°-1
=
+1 2 3×
-11 2
×2 2
,2 2
=1+
,1 2
=
.3 2
计算: (1)|2
(2)
|
(1)|2
-3|-(-2
)-2+1 2
,18
=3-2
-4+32
,2
=
-1;2
(2)
+sin45°cos45°,cos60° 3sin30°-1
=
+1 2 3×
-11 2
×2 2
,2 2
=1+
,1 2
=
.3 2