问题 解答题
(1)计算:
2
2
-1
-
8
-(
2
+1)0

(2)|-
1
2
|+sin30°+2cos245°-
1
3
tan260°
答案

(1)原式=

2(
2
+1)
2-1
-2
2
-1,

=2

2
+2-2
2
-1,

=1;

(2)原式=

1
2
+
1
2
+2×(
2
2
)
2
-
1
3
×(
3
)
2

=

1
2
+
1
2
+1-1,

=1.

判断题
判断题