问题
解答题
计算题: (1)(-1)2008+π0-(
(2)(3
(3)
(4)
|
答案
(1)原式=1+1-3+2
=1;
(2)原式=(9
+2
-22
)÷42 2
=8
÷42 2
=2;
(3)原式=
(12 3+
) 2 (
-3 2)(
+3
) 2
=
+36 24
=6+2
;6
(4)原式=4
-3
+3-3
-1-2+3 3
=3
.3
计算题: (1)(-1)2008+π0-(
(2)(3
(3)
(4)
|
(1)原式=1+1-3+2
=1;
(2)原式=(9
+2
-22
)÷42 2
=8
÷42 2
=2;
(3)原式=
(12 3+
) 2 (
-3 2)(
+3
) 2
=
+36 24
=6+2
;6
(4)原式=4
-3
+3-3
-1-2+3 3
=3
.3