问题 单项选择题

(),国防科技大学计算机研究所研制出被命名为“银河”的大型计算机系统。从此,我国踏进了世界研制巨型机的行列。

A.1983年12月

B.1982年12月

C.1981年12月

答案

参考答案:A

问答题

已知C源程序如下:
/* Input today’s date,output tomorrow’s date */
/* version 2 */
#include <stdio.h>
struct ydate
int day; int month; int year; ;
int leap(struct ydate d)
if((d.year%4==0&&d.year%100!=0)||(d.year%400==0)
return 1;
else
return 0;

int numdays(struct ydate d)
int day;
static int daytab[]=
31,28,31,30,31,30,31,31,30,31,30,31;
if (leap (d)&&d.month==2)
day=29;
else
day=daytab [d.month-1];
return day;

int main (void)
struct ydate today, tomorrow;
printf("format of date is: year,month, day
输入的年、月、日之间应用逗号隔开\n"
printf(" today is: ") ;
scanf ("%d, %d, %d", &today. year, &today.month, &today. day) ;
while(0>=today.year|| today.year>65535||0>=today.month||today.month>12)||0>=
today, day||today, day>numdays (today))
printf("input date error! reenter the day!\n");
printf("today is :");
scanf ("%d, %d, %d", &today. year, &today.month, &today. day);

if (today. day! =numdays (today))
tomorrow.year:today.year;
tomorrow.month=today.month;
tomorrow.day=today.day+1;

else if(today.month==12)
tomorrow.year:today.year+1;
tomorrow.month=1;
tomorrow.day=1;

else
tomorrow.year=today.year;
tomorrow.month=today.month+1;
tomorrow.day=1;

printf("tomorrow is :%d,%d,%d\n\n",
tomorrow.year, tomorrow.month, tomorrow.day);

(1)画出程序中所有函数的控制流程图。
(2)设计一组测试用例,使该程序所有函数的语句覆盖率和分支覆盖率均能达到100%。如果认为该程序的语句或分支覆盖率无法达到100%,则说明为什么。

单项选择题