问题
选择题
函数f(x)=loga(2x+1)(a>0,a≠1)的图象过定点( )
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答案
∵对数函数f(x)=logax(a>0,a≠1)的图象过定点(1,0),
∴令2x+1=1,解得x=0,
此时f(0)=loga1=0,即f(x)的图象过定点(0,0),
故选:C.
函数f(x)=loga(2x+1)(a>0,a≠1)的图象过定点( )
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∵对数函数f(x)=logax(a>0,a≠1)的图象过定点(1,0),
∴令2x+1=1,解得x=0,
此时f(0)=loga1=0,即f(x)的图象过定点(0,0),
故选:C.
从Ⅱ栏中找出与Ⅰ栏相匹配的句子。(满分5分) Ⅰ 小题1:Did you enjoy yourself last Sunday, Li Hui? 小题2:Must we come to school tomorrow? 小题3:Who’s speaking? 小题4:What kind of music do you like? 小题5:Knowledge is important to us.
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