问题 解答题
(1)计算:①
12
-sin60°+(1-tan60°)-1;②
a2-2a+1
a-1
-(a-2).
(2)解方程:①
2
x
=
3
x+3
;②x2-3x+2=0.
答案

(1)①

12
-sin60°+(1-tan60°)-1

=2

3
-
3
2
+
1
1-
3

=2

3
-
3
2
-
1+
3
2

=

3
-
1
2

a2-2a+1
a-1
-(a-2)

=a-1-a+2

=1

(2)①

2
x
=
3
x+3

2(x+3)=3x

x=6

经检验x=6是原方程的根.

②x2-3x+2=0.

(x-2)(x-1)=0

x1=1,x2=2.

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