问题
解答题
计算题 (1)(2×102)×(3×103) (2)-15+(
(3)(2x)3-y3÷(16xy2) (4)(x-1)(x2+x+1) |
答案
(1)(2×102)×(3×103),
=2×3×102+3,
=6×105;
(2)-15+(
)2+(π-3)0,1 2
=-1+
+1,1 4
=
;1 4
(3)(2x)3•y3÷(16xy2),
=8x3•y3÷(16xy2),
=
x2y;1 2
(4)(x-1)(x2+x+1),
=(x-1)(x2+x+1),
=x3+x2+x-x2-x-1,
=x3-1;