问题
解答题
计算:(1)|
(2)先化简,再求值:(a-
|
答案
(1)|
-2|+20110-(-3
)-1+tan60°,1 3
=2-
+1-(-3)+3
,3
=6;
(2)原式=a2-3-(a2-6a),
=a2-3-a2+6a,
=6a-3,
当a=
+5
时,原式=6(1 2
+5
)-3=61 2
.5
计算:(1)|
(2)先化简,再求值:(a-
|
(1)|
-2|+20110-(-3
)-1+tan60°,1 3
=2-
+1-(-3)+3
,3
=6;
(2)原式=a2-3-(a2-6a),
=a2-3-a2+6a,
=6a-3,
当a=
+5
时,原式=6(1 2
+5
)-3=61 2
.5