问题
填空题
计算:(-2)2003×(-0.5)2004=______;(-2)100+(-2)101=______.
答案
(-2)2003×(-0.5)2004
=(-2)2003×(-0.5)2003×(-0.5)
=[(-2)×(-0.5)]2003×(-0.5)
=1×(-0.5)
=-0.5;
(-2)100+(-2)101=(-2)100×(1-2)=-2100.
计算:(-2)2003×(-0.5)2004=______;(-2)100+(-2)101=______.
(-2)2003×(-0.5)2004
=(-2)2003×(-0.5)2003×(-0.5)
=[(-2)×(-0.5)]2003×(-0.5)
=1×(-0.5)
=-0.5;
(-2)100+(-2)101=(-2)100×(1-2)=-2100.