问题
选择题
已知等差数列{an}的前n项和为Sn,若S2=10,S5=55,则过点P(n,an)和Q(n+2,an+2)(n∈N*)的直线的斜率为( )
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答案
由题意得:S2=2a1+d=10①,S5=5a1+10d=55②,
②×2-①×5得:15d=60,解得d=4,
又P(n,an)和Q(n+2,an+2),
则过P和Q的斜率k=
=d=4.an+2-an (n+2)-n
故选C
已知等差数列{an}的前n项和为Sn,若S2=10,S5=55,则过点P(n,an)和Q(n+2,an+2)(n∈N*)的直线的斜率为( )
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由题意得:S2=2a1+d=10①,S5=5a1+10d=55②,
②×2-①×5得:15d=60,解得d=4,
又P(n,an)和Q(n+2,an+2),
则过P和Q的斜率k=
=d=4.an+2-an (n+2)-n
故选C