问题
选择题
等差数列{an}的前n项和为Sn,已知S8=132,Sm=690,Sm-8=270(m>8),则m为( )
A.2l
B.20
C.19
D.18
答案
Sm-Sm-8=am-7+am-6+…+am=690-270=420①,而S8=a1+a2+…+a8=132②,
利用等差数列的性质及①+②得:8(a1+am)=552,则a1+am=69
又Sm=
=m(a1+am) 2
=690,解得m=2069m 2
故选B