问题
解答题
计算: (1)(
(2)先化简,再求值:(5a2-3b2)+(3b2-4a2)-
|
答案
(1)原式=
-1 4
+1+5-1 4
×9 4
=6-1=5;4 9
(2)原式=5a2-3b2+3b2-4a2-2ab+1=a2-2ab+1,
当a=1,b=-1时a2-2ab+1=1-2×1×(-1)+1=4.
计算: (1)(
(2)先化简,再求值:(5a2-3b2)+(3b2-4a2)-
|
(1)原式=
-1 4
+1+5-1 4
×9 4
=6-1=5;4 9
(2)原式=5a2-3b2+3b2-4a2-2ab+1=a2-2ab+1,
当a=1,b=-1时a2-2ab+1=1-2×1×(-1)+1=4.