问题
解答题
计算: (1)6(2ab+3a)-7(4a-ab) (2)5x2-[12x-(
(3)18-[25-(-7)-(-4)]+22-33 (4)|-7
(5)21°44′÷4 (6)15°24′+32°47′-6°55′. |
答案
(1)原式=12ab+18a-28a+7ab=19ab-10a;
(2)原式=5x2-12x+(
x-6)-4x=5x2-1 3
x-6;47 3
(3)原式=18-(25+7+4)+4-27=18-36+4-27=-41;
(4)原式=
×(-15 2
)×1 6
-12 5
×(-9 2
)=-3+3=0;2 3
(5)原式=5°26′;
(6)原式=41°16′.