问题
选择题
已知数列{an}的前n项和为Sn,且Sn=n2+2n,则a9=( )
A.20
B.17
C.18
D.19
答案
由题意可得Sn=n2+2n,
所以a9=S9-S8
=92+2×9-82-2×8
=19
故选D
已知数列{an}的前n项和为Sn,且Sn=n2+2n,则a9=( )
A.20
B.17
C.18
D.19
由题意可得Sn=n2+2n,
所以a9=S9-S8
=92+2×9-82-2×8
=19
故选D